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What volume of 3.00 M KOH is required to prepare 0.150 L of 1.00 M KOH?

a) 0.045 L
b) 0.050 L
c) 0.075 L
d) 0.100 L

1 Answer

4 votes

Final answer:

To prepare a diluted solution, you can use the formula C₁V₁ = C₂V₂, where C₁ and C₂ are the initial and final concentrations, and V₁ and V₂ are the initial and final volumes, respectively. In this case, the volume of 3.00 M KOH required to prepare 0.150 L of 1.00 M KOH is 0.050 L. The correct option is b.

Step-by-step explanation:

To calculate the volume of a concentrated solution needed to prepare a diluted solution, you can use the formula:

C1V1 = C2V2

Where C1 and C2 are the initial and final concentrations, and V1 and V2 are the initial and final volumes, respectively.

In this case, we are given:

  • C1 = 3.00 M (concentration of the initial solution)
  • V1 = ? (volume of the initial solution)
  • C2 = 1.00 M (concentration of the final solution)
  • V2 = 0.150 L (volume of the final solution)

Plugging these values into the formula, we have:

3.00 M * V1 = 1.00 M * 0.150 L

V1 = 0.050 L

Therefore, the volume of 3.00 M KOH required to prepare 0.150 L of 1.00 M KOH is 0.050 L. Option b. is the correct one.

User Danila Ganchar
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