Final answer:
The efficiency of the heat engine operating between 500 K and 125 K is calculated using the Carnot efficiency formula, resulting in a 75% efficiency. The correct answer is B) 75%.
Step-by-step explanation:
The efficiency of a heat engine operating between two temperatures can be calculated using the theoretical limit set by the Carnot efficiency, which is given by:
Efficiency (η) = 1 - (Tc/Th)
where:
For a heat engine operating between a hot reservoir at 500 K and a cold reservoir at 125 K:
Efficiency (η) = 1 - (125K / 500K)
Efficiency (η) = 1 - 0.25
Efficiency (η) = 0.75 or 75%
Therefore, the correct answer is B) 75%.