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Multiply 1235 by 3. The number of pieces in the minimal set are (fill in unused symbols with zero):

a) Flats: 6, Longs: 1, Units: 0, Long-flats: 6
b) Flats: 6, Longs: 1, Units: 8, Long-flats: 6
c) Flats: 1, Longs: 8, Units: 5, Long-flats: 6
d) Flats: 1, Longs: 0, Units: 8, Long-flats: 6

User Rajakvk
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1 Answer

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Final answer:

The correct answer after multiplying 1235 by 3 is 3705. The products are then categorized into flats (1000s), longs (100s), units (1s), and long-flats (10000s), giving us 3 flats, 7 longs, 5 units, and 0 long-flats, which was not an option provided.

Step-by-step explanation:

The question involves performing a multiplication operation and then understanding base-10 place value to allocate the product into the different categories of flats, longs, units, and long-flats, which seems to be a part of a base-10 block representation system for numbers. To begin, we multiply 1235 by 3. The process is as follows:

  • 3 × 5 = 15, write down 5 and carry over 1
  • 3 × 3 = 9, plus the 1 carried over = 10, write down 0 and carry over 1
  • 3 × 2 = 6, plus the 1 carried over = 7, write this down
  • 3 × 1 = 3, so we write this down

Therefore, 3 × 1235 = 3705. Now we need to place these into the minimal set of flats (1000s), longs (100s), units (1s), and long-flats (presumably 10000s).

Flats: We have 3705, so the number of flats (1000s) is 3.
Longs: There are 7 longs (100s) since we have 700 in 3705.
Units: We have 5 units.
Long-flats: There are 0 long-flats as we do not reach the 10000s place.

The correct answer to fill in would be:

  • Flats: 3
  • Longs: 7
  • Units: 5
  • Long-flats: 0

Therefore, none of the provided options are correct. We had to process the multiplication first and then refer to the size of each category in a place value system to identify the quantity of each type of block needed to represent the product.

User RandomB
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