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Which options cannot be the degree of a polynomial equation that has only imaginary √s and no real √?

A. 4
B. 5
C. 6
D. 7
E. 8
F. 9

User AgentKnopf
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1 Answer

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Final answer:

The options that cannot be the degree of a polynomial equation with only imaginary square roots and no real square roots are 5, 7, and 9.

Step-by-step explanation:

In order to determine which options cannot be the degree of a polynomial equation that has only imaginary square roots (symbolized as √-1), we need to understand some key concepts.

The degree of a polynomial equation is the highest power of the variable. For example, if the polynomial equation is 3x^2 + 5x + 2, the highest power is 2 and therefore the degree is 2.

In a polynomial equation with only imaginary square roots and no real square roots, the degree must be an even number. This is because imaginary square roots always come in pairs: if there is one, there must be another one that is its negative counterpart.

Let's go through the options:

A. 4 - This can be the degree of a polynomial equation with only imaginary square roots, as it is an even number.

B. 5 - This cannot be the degree of a polynomial equation with only imaginary square roots, as it is an odd number.

C. 6 - This can be the degree of a polynomial equation with only imaginary square roots, as it is an even number.

D. 7 - This cannot be the degree of a polynomial equation with only imaginary square roots, as it is an odd number.

E. 8 - This can be the degree of a polynomial equation with only imaginary square roots, as it is an even number.

F. 9 - This cannot be the degree of a polynomial equation with only imaginary square roots, as it is an odd number.

Therefore, the options that cannot be the degree of a polynomial equation that has only imaginary square roots and no real square roots are B, D, and F.

User Jed Lynch
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