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What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?

A) 3x + 5y = -9
B) 3x + 5y = 9
C) 5x - 3y = -15
D) 5x - 3y = 15

User Kleskowy
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1 Answer

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Final answer:

The equation of the perpendicular line is y = (-1/3)x + 1.

Step-by-step explanation:

To find the equation of the line that is perpendicular to a given line and passes through a specific point, we use the fact that the slopes of perpendicular lines are negative reciprocals of each other. The given line has a slope of 3, so the perpendicular line will have a slope of -1/3. To find the equation, we can use the point-slope form of a line, which is y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Plugging in the values x1 = 3, y1 = 0, and m = -1/3, we get the equation y - 0 = (-1/3)(x - 3), which simplifies to y = (-1/3)x + 1.

User AlexChaffee
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