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If angle EAB and angle DCB are right angles, how do you prove triangle EAB is congruent to triangle DCB?

1 Answer

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To prove that
\triangle EAB \cong \triangle DCB, we can use the side-angle-side (SAS) congruence criteria.

To prove that triangle EAB is congruent to triangle DCB, we need to show that they have congruent sides and congruent angles.

Since
\angle EAB and
\angle DCB are both right angles, they are congruent. This is because all right angles are congruent.

Next, we can look at the sides. We know that AB = CD because corresponding sides of congruent triangles are congruent.

Also, EA = CB because they are both parts of the same line, so they have the same length.

Therefore,
\triangle EAB
\cong
\triangle DCB by the side-angle-side (SAS) congruence criteria.

The probable question may be: "If
\angle EAB and
\angle DCB are right angles, how do you prove
\triangle EAB
\cong
\triangle DCB?"

User Bumbleshoot
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