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AABC has A_(3, 6), B(2, 1), and C(19, 5)_ as its vertices.
The length of side AB is (insert units).
LABC (insert units).
The length of side BCS (insert units).
The length of side AC (insert units).

User Jeannie
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1 Answer

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Final answer:

The length of side AB is √26 units. LABC is √257 units. The lengths of side BCS and AC are also √26 and √257 units, respectively.

Step-by-step explanation:

The length of side AB can be found using the distance formula:

AB = √[(x2 - x1)^2 + (y2 - y1)^2]

AB = √[(2 - 3)^2 + (1 - 6)^2]

AB = √[1 + 25]

AB = √26

LABC can be found using the Pythagorean Theorem:

LABC = √[(AC)^2 - (BC)^2]

LABC = √[(19 - 3)^2 + (5 - 6)^2]

LABC = √[16^2 + 1]

LABC = √257

The lengths of side BCS and AC can be found using the distance formula in the same way as AB. Their lengths are also √26 and √257, respectively.

User Hexception
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