Question

In Bob's cooler there are 6 bottles of soda and 7 bottles of water. Bob is going to choose 7 bottles at random from the cooler to give to his friends. What is the probability that he will choose 4 sodas and 3 waters? Round your answer to three decimal places.

Answer 1

The probability that Bob will choose 4 sodas and 3 waters from the cooler is approximately 0.308.

Step-by-step explanation:

To find the probability, we need to calculate the number of ways Bob can choose 4 sodas out of 6 and 3 waters out of 7, and divide it by the total number of ways he can choose 7 bottles out of 13:

Number of ways to choose 4 sodas = C(6, 4)

= 15

Number of ways to choose 3 waters = C(7, 3)

= 35

Total number of ways to choose 7 bottles = C(13, 7)

= 1716

So, the probability that Bob will choose 4 sodas and 3 waters is:

P(4 sodas and 3 waters) = (15 * 35) / 1716

≈ 0.308