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A Ship A steaming due north, at 10 km per hour sight at noon, a second ship B in a direction due east and 1km away steaming north east at 5 km per hour. Calculate to the nearest degrees the bearing of A from B at 12:15 pm?

A. 51°
B. 63°
C. 69°
D. 75°

User Teasha
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1 Answer

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Final answer:

To find the bearing of ship A from ship B, we can calculate the velocity of ship B relative to ship A and find the angle between the velocity vector and the north direction.

Step-by-step explanation:

To find the bearing of ship A from ship B, we can use vector addition. Let's calculate the velocity of ship B relative to ship A. Ship B is steaming northeast at 5 km/hr, which can be represented as a vector of magnitude 5 km/hr and direction of 45 degrees east of north.

Ship A is moving due north at 10 km/hr. The velocity of ship B relative to ship A is the vector subtraction of the velocity of ship A from the velocity of ship B. This can be calculated as:

Velocity of B relative to A = Velocity of B - Velocity of A = 5 km/hr at 45 degrees east of north - 10 km/hr at 0 degrees north.

By taking the difference:

Velocity of B relative to A = 5 km/hr at 45 degrees east of north - 10 km/hr at 0 degrees north = 5 km/hr at 45 degrees east of north - 10 km/hr at 90 degrees east of north

= -5 km/hr at 45 degrees east of north - 10 km/hr at 0 degrees east of north

= -15 km/hr at 45 degrees east of north

The bearing is the angle between the velocity vector of B relative to A and the north direction. Therefore, the bearing of A from B at 12:15 pm is:

Bearing = 360 degrees - 45 degrees = 315 degrees.

User Mossroy
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