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Let f(x)=√x and g(x)=3x+2. Find the range of f⋅g(x).

a) f⋅g(x)=3√x+2
b) f⋅g(x)= √3x+2
c) f⋅g(x)= √3x+4
d) f⋅g(x)=3√x+4

User Titsjmen
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Final answer:

The range of f⋅g(x) will be all real numbers greater than or equal to 0.

Step-by-step explanation:

The range of f⋅g(x) can be found by substituting the given functions f(x) and g(x) into the expression f⋅g(x).

f(x) = √x and g(x) = 3x + 2

So, f⋅g(x) = √x * (3x + 2)

To find the range, we need to determine the possible values that f⋅g(x) can take. In this case, the range will depend on the domain of x. Since f(x) = √x, the domain of x must be greater than or equal to 0. Therefore, the range of the function f⋅g(x) will be all real numbers greater than or equal to 0.

User Serhan
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