Question

JE

Write an equation for a line perpendicular to y = 3a + 3 and passing through the point (-6,6)

Answer 1

Explanation:

A line that is perpendicular to another will have the opposite slope.

y =
`-(1)/(3)`a + b

To find b, substitute y and a with the given values

6 =
`-(1)/(3)`(-6) + b

6 = 2 + b

-2 -2

4 = b

thus

y =
`-(1)/(3)`a + 4

Answer 2

y= -1/3a + 4

Find the negative inverse of 3. The inverse of 3 is 1/3 and negative 1/3 would be -1/3.

The slope is found so now you plug in the number to the point given.

-1/3 (-6) = 2
To get from 2 to 6, you add 4.