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Find a1 in a geometric series for which S8 = 765, n = 8, and r= 2.

User Glassomoss
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Final answer:

To find a1 in a geometric series, you can use the formula S_n = a_1(1 - r^n)/(1 - r), where S_n is the sum of the series, a_1 is the first term, r is the common ratio, and n is the number of terms. Given the values S_8 = 765, n = 8, and r = 2, the first term a_1 is -3.

Step-by-step explanation:

To find a1 in a geometric series, we can use the formula:



S_n = a_1(1 - r^n)/(1 - r)



where S_n is the sum of the series, a_1 is the first term, r is the common ratio, and n is the number of terms.



Given that S_8 = 765, n = 8, and r = 2, we can plug these values into the formula to find a_1:



765 = a_1(1 - 2^8)/(1 - 2)



765 = a_1(1 - 256)/(-1)



765 = a_1(-255)



To solve for a_1, we can divide both sides of the equation by -255:



a_1 = 765/-255



a_1 = -3

User Speedy
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