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Suppose you own a small business with four employees, namely Roberto, Sandra, Petra, and Lee. At the end of the year, you have set aside $1800 to divide among them as a bonus. You have two categories in place for your bonus system. An exceptional employee receives one amount, and an average employee receives half that amount. You have rated Roberto and Sandra exceptional and Petra and Lee average employees. How much bonus should each employee receive?

a) $450 for Roberto and Sandra, $225 for Petra and Lee
b) $360 for Roberto and Sandra, $180 for Petra and Lee
c) $225 for Roberto and Sandra, $112.50 for Petra and Lee
d) $180 for Roberto and Sandra, $90 for Petra and Lee

1 Answer

1 vote

Final answer:

The correct distribution of the $1800 bonus is that each exceptional employee, Roberto and Sandra, should receive $600, and each average employee, Petra and Lee, should get $300, which was not listed in the provided options.

Step-by-step explanation:

Let's calculate the bonuses for the four employees, namely Roberto, Sandra, Petra, and Lee, with a total bonus pool of $1800. Since we have two exceptional employees and two average employees, we can designate the amount for an exceptional employee as ‘x’ and for an average employee as 'x/2'.

We know that:

  • Roberto and Sandra are exceptional, receiving 'x' each.
  • Petra and Lee are average, receiving 'x/2' each.

Therefore, the calculation will be:

2x (Roberto + Sandra) + 2(x/2) (Petra + Lee) = $1800
2x + x = $1800
3x = $1800
x = $1800 / 3
x = $600

So the exceptional employees (Roberto and Sandra) receive $600 each and the average employees (Petra and Lee) receive $300 each ($600/2).

This means the correct answer is none of the provided options:

  • (a) $450 for Roberto and Sandra, $225 for Petra and Lee
  • (b) $360 for Roberto and Sandra, $180 for Petra and Lee
  • (c) $225 for Roberto and Sandra, $112.50 for Petra and Lee
  • (d) $180 for Roberto and Sandra, $90 for Petra and Lee

The answer should be $600 for Roberto and Sandra, and $300 for Petra and Lee.

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