Question

Calculate the molar concentration of YOH and the relative atomic mass of the element Y in the neutralization reaction

HCl+YOH→YCl+H 2O. Given:
HCl=36.5, and the volumes and concentrations of the solutions.
A) Molar concentration of YOH = 0.28 mol/dm³; Relative atomic mass of Y = 40.1 (Calcium)
B) Molar concentration of YOH = 0.25 mol/dm³; Relative atomic mass of Y = 16 (Oxygen)
C) Molar concentration of YOH = 0.35 mol/dm³; Relative atomic mass of Y = 23 (Vanadium)
D) Molar concentration of YOH = 0.32 mol/dm³; Relative atomic mass of Y = 12 (Carbon)

Answer 1

To determine the correct molar concentration of YOH and the relative atomic mass of the element Y, we utilize the stoichiometry of the reaction and the molar mass of HCl and OH-. Further information or additional data about the reaction is needed to identify the correct option among A, B, C, or D.

Step-by-step explanation:

To calculate the molar concentration and the relative atomic mass of the element Y in the neutralization reaction HCl + YOH → YCl + H₂O, we need to consider stoichiometry and the molar mass concept. The given molar concentration of HCl and the volume used will help to determine the moles of HCl reacted. Since this is a 1:1 reaction, the moles of YOH will be the same as HCl.

Using the mass of HCl (36.5 g/mol), we can determine the mass of YOH if we have the number of moles and molar concentration of YOH. The relative atomic mass of Y can be deduced by subtracting the molar masses of OH (17 g/mol) from the molar mass of YOH.

The correct molar concentration of YOH and relative atomic mass of the element Y can be found by process of elimination or by using additional information about the reaction that was provided in the question.