Final answer:
The power rating of an electric drill that transfers 180 kJ of energy over 2 minutes is calculated to be 1,500 W, which is 1.5 kW. The correct option is A. 1.5 kW.
Step-by-step explanation:
The question is asking for the power rating of an electric drill that transfers 180 kJ of energy over 2 minutes. Power is the rate of energy transfer and is calculated using the formula:
P = E/t,
where P is power in watts (W), E is energy in joules (J), and t is time in seconds (s).
In this case, we have:
E = 180,000 J (since 1 kJ = 1,000 J),
t = 2 minutes × 60 seconds/minute = 120 seconds.
So, the power rating is calculated as:
P = 180,000 J / 120 s = 1,500 W.
Therefore, the power rating of the electric drill is 1.5 kW which corresponds to option A.