Question

Two students finish a conversation and walk away from each other. If one person walks at 4 ft/sec and the other at 3 ft/sec, how fast is the distance between the two changing at time t=10 sec?

A. 5 ft/sec
B. 7 ft/sec
C. 1 ft/sec
D. 12 ft/sec

Answer 1

The rate at which the distance between the two students is changing at time t=10 sec is 1 ft/sec.

Step-by-step explanation:

To find the rate at which the distance between the two students is changing, we can use the formula for the rate of change of distance between two moving objects. The formula is given by:

Rate of change of distance = |velocity of A - velocity of B|

Given that one person walks at 4 ft/sec and the other at 3 ft/sec, we substitute these values into the formula:

Rate of change of distance = |4 ft/sec - 3 ft/sec|

Rate of change of distance = 1 ft/sec

Therefore, the distance between the two students is changing at a rate of 1 ft/sec at time t=10 sec.