Question

0.67 mol of MgCl2 in a 0.50 kg water. How many moles of ions are present?

(A) 2.01 mol
(B) 2.67 mol
(C) 3.67 mol
(D) 1.34 mol

Answer 1

To determine the number of moles of ions present, we need to calculate the number of moles of MgCl2. For every 1 mole of MgCl2, there are 3 moles of ions (2 moles of Cl- and 1 mole of Mg2+).

Therefore, the number of moles of ions is 3 times the number of moles of MgCl2, which is 0.67 mol x 3 = 2.01 mol.

Step-by-step explanation:

To determine the number of moles of ions present, we need to calculate the number of moles of MgCl2. Given that there are 0.67 mol of MgCl2, we can use the stoichiometry of the compound to determine the number of moles of ions.

For every 1 mole of MgCl2, there are 3 moles of ions (2 moles of Cl- and 1 mole of Mg2+). Therefore, the number of moles of ions is 3 times the number of moles of MgCl2, which is 0.67 mol x 3 = 2.01 mol.

Therefore, the correct answer is (A) 2.01 mol.