Question

an object of 5kg is attached to a rope of length 4m is Rotating horizontally at 8m/s horizontally 20m above the ground if the rope is suddenly cut what is the horizontal distance travelled by the object? Please guys help

Answer 1

16 meters

Step-by-step explanation:

When the rope is suddenly cut the object moving tangent at the circle. In that moment the gravity act in the object making it falls.

First we need to find how much time de object take to reach at the ground.

VERTICALLY EQUATION:

`h(t)=h-v*t-(g)/(2) t^(2) \\`

g=acceleration of gravity=10m/s²

v= vertical velocity =0m/s

h=vertical altitude =20m

We will find t such that h(t)=0

`0=20-5t^(2) \\\\5t^(2) =20\\\\t^(2) =4\\\\t=2s`

HORIZONTALLY EQUATION:

*horizontally we do not have acceleration

`D(t)=v*t`

v=horizontal velocity

D(t=2) is the horizontal distancetravelled by the object:

`D(2)=8*2\\\\D(2)=16m`