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Two numbers differ by 40. If the smaller number is 10 more than half of the biggest one, find the biggest number.

a. 60
b. 80
c. 100
d. 120

User Peaceman
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1 Answer

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Final answer:

To find the biggest number, set up an equation based on the given information. Solve the equations to find the value of the biggest number, which is 100.

Step-by-step explanation:

To find the biggest number, we need to set up an equation based on the given information.

Let's assume the smaller number is x and the bigger number is y.

According to the problem, y - x = 40.

Also, it is given that the smaller number (x) is 10 more than half of the bigger number (y/2).

So, the equation is x = y/2 + 10.

We can now solve these two equations to find the value of y, the biggest number.

Substituting y/2 + 10 for x in the first equation: y - (y/2 + 10) = 40.

Simplifying, we get (2y - y)/2 = 40 + 10.

Combining like terms, y/2 = 50.

Multiplying both sides by 2, y = 100.

Therefore, the biggest number is 100.

User Thinker
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