Final answer:
To calculate the energy of a mole of photons emitted when the electron transitions from the n = 6 to n = 3 level in a hydrogen atom, use the equation ΔE = E6 - E3, where E6 and E3 are the energies of the corresponding energy levels. Convert the energy difference from electron volts to joules using the conversion factor 1 eV = 1.602 x 10⁻¹⁹ J.
Step-by-step explanation:
To calculate the energy of a photon emitted when the electron transitions from the n = 6 to n = 3 level in a hydrogen atom, we can use the energy difference equation between energy levels:
ΔE = E6 - E3
Substituting the energy levels:
ΔE = (-13.6 eV/6²) - (-13.6 eV/3²)
We can convert this energy difference from electron volts (eV) to joules (J) using the conversion factor 1 eV = 1.602 x 10⁻¹⁹ J. Therefore, the energy of a mole of photons emitted is:
Energy = ΔE x Avogadro's number x conversion factor
where Avogadro's number is 6.022 x 10²³.