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Given the reaction: 2 Ba(s) + O₂(g) → 2 BaO(s) + 1107 kJ. How much heat is released when 5.75 g of BaO is produced? (Show work)

User Slavica
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Final answer:

To find the heat released when 5.75 g of BaO is produced, calculate the moles of BaO and use the given reaction enthalpy. The calculation yields that 20.8 kJ of heat is released.

Step-by-step explanation:

The question deals with the calculation of heat released during a chemical reaction. Given the reaction 2 Ba(s) + O₂(g) → 2 BaO(s) + 1107 kJ, we can calculate the amount of heat released when 5.75 g of BaO is produced. First, we find the molar mass of BaO to determine how many moles of BaO correspond to 5.75 g. The molar mass of BaO is 137.33 g/mol for Ba and 16.00 g/mol for O, which gives 153.33 g/mol for BaO. Now, we calculate the moles:

Moles of BaO = 5.75 g divided by 153.33 g/mol = 0.0375 mol

Since the reaction shows that 2 moles of BaO release 1107 kJ of heat, we can set up a proportion to solve for the amount of heat released by 0.0375 mol:

Heat released = 0.0375 mol × (1107 kJ / 2 mol) = 20.8 kJ

Therefore, 20.8 kJ of heat is released when 5.75 g of BaO is produced.

User Ravi Hamsa
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