Question

Two charges, -2nC and 2nC, are located at x = -0.1cm and x = 0.1cm, respectively. Determine the electric field at the points (-1 cm, 0 cm), (1 cm, 0 cm), (0 cm, 1cm), (0 cm, -1 cm), and (1 cm, 1 cm).

a) [ E = 1.8 times 10^4 , N/C, , 0 , N/C, , 0 , N/C, , 1.8 times 10^4 , N/C, , 2.54 times 10^4 , N/C ]

b) [ E = 2.54 times 10^4 , N/C, , 0 , N/C, , 0 , N/C, , 2.54 times 10^4 , N/C, , 1.8 times 10^4 , N/C ]

c) [ E = 1.8 times 10^4 , N/C, , 0 , N/C, , 2.54 times 10^4 , N/C, , 0 , N/C, , 2.54 times 10^4 , N/C ]

d) [ E = 2.54 times 10^4 , N/C, , 0 , N/C, , 2.54 times 10^4 , N/C, , 1.8 times 10^4 , N/C, , 0 , N/C ]

Answer 1

The electric field at different points due to given charges is calculated using the formula E = k * (q / r^2).

Step-by-step explanation:

The electric field at a point due to a charge is given by the formula:

E = k * (q / r^2)

where E is the electric field, k is the Coulomb's constant (8.99 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the charge.

For the given charges, -2nC and 2nC, located at x = -0.1cm and x = 0.1cm respectively, we can calculate the electric field at each of the given points.

The electric field at (-1 cm, 0 cm) is 1.8 x 10^4 N/C.

The electric field at (1 cm, 0 cm) is 0 N/C.

The electric field at (0 cm, 1 cm) is 0 N/C.

The electric field at (0 cm, -1 cm) is 0 N/C.

The electric field at (1 cm, 1 cm) is 2.54 x 10^4 N/C.