Question

You built the wedges for a bean bag game. The goal is to toss the bean bags into the open hole. The final step is to paint these. You are only painting the top of the game, the outer sides of both wedges, and the back sides of both wedges. Estimate the surface area of these parts of the game. Use 3.14 to approximate pi.

a) ( A ≈ 2 × left(3.14 ×radius²right) )
b) ( A ≈ 3 × left(3.14 ×radius²right) )
c) ( A ≈ 4 × left(3.14 ×radius²right) )
d) ( A ≈ left(3.14 ×radius²right) + left(2 ×base arearight) )

Answer 1

The estimation of the surface area for painting a bean bag game likely includes both the areas of the circles and the additional surfaces. The best approximation seems to be option (d), acknowledging both the circular areas and the base area of the wedges.

Step-by-step explanation:

The estimation of the surface area for a bean bag game involves calculating the areas of the different parts of the game that will be painted. According to the multiple-choice options provided, we need to select an approximation that considers both the area of the circle (where the bags are tossed into) and the additional surfaces being painted. As the base area is mentioned separately from the circular area, option (d) A ≈ (3.14 × radius²) + (2 × base area) may best represent our calculation for the surface area to be painted since it encompasses both the area of the circle and the base area of the wedges.

For accurate calculation, you'd need to add the area of the circles and the sides and back areas of the wedges. However, since the question seems to center around estimating the area using the radius of the circles, we are not provided with the exact base area, but we assume it would be included in the final estimate as per option (d).