Question

Looking out to the sea, the visibility in miles from a certain spot on a cliff can be calculated using the function d(x)= √1.5x, where x is the height in feet above sea level. Suppose Sasha's brother walks through elevations ranging from 8 ft to 48 ft. What are the minimum and maximum distances that he can see?

A. Minimum distance: √12 miles; Maximum distance: √72 miles
B. Minimum distance: √16 miles; Maximum distance: √72 miles
C. Minimum distance: √12 miles; Maximum distance: √48 miles
D. Minimum distance: √16 miles; Maximum distance: √48 miles

Answer 1

The minimum and maximum distances that Sasha's brother can see are √12 miles and √72 miles respectively.

Step-by-step explanation:

To find the minimum and maximum distances that Sasha's brother can see, we need to plug in the given elevations into the function d(x) = √1.5x. The elevations range from 8 ft to 48 ft.

For the minimum distance, we substitute x = 8 into the function:

d(8) = √1.5(8) = √12 miles.

For the maximum distance, we substitute x = 48 into the function:

d(48) = √1.5(48) = √72 miles.

So, the minimum distance Sasha's brother can see is √12 miles and the maximum distance is √72 miles. Therefore, the correct answer is B. Minimum distance: √12 miles; Maximum distance: √72 miles.