Final answer:
Using Charles's Law (V1/T1 = V2/T2), the volume of a gas increasing from 7.0 L at 7.0°C to a) 7.08 L at 10.0°C was calculated by first converting the temperatures to Kelvin and then applying the formula to solve for the new volume.
Step-by-step explanation:
The question is asking about the change in volume of a gas when its temperature is increased, holding the pressure constant. To solve this, we use Charles's Law, which states that the volume of a gas is directly proportional to its absolute temperature (measured in Kelvin), as long as the pressure is constant. The law can be expressed as V1/T1 = V2/T2 where V1 is the initial volume, V2 is the final volume, T1 is the initial temperature in Kelvin, and T2 is the final temperature in Kelvin.
To solve the problem given in the question:
- Convert the temperatures from Celsius to Kelvin, which involves adding 273.15 to each Celsius temperature. This gives us T1 = 7.0 + 273.15 = 280.15 K and T2 = 10.0 + 273.15 = 283.15 K.
- Insert the values into Charles's Law and solve for V2: (7.0 L / 280.15 K) = (V2 / 283.15 K).
- Multiply both sides by 283.15 K to isolate V2, which results in V2 = 7.08 L.
Therefore, the correct answer is (a) 7.08 L, as the new volume of the gas when the temperature is increased to 10.0°C.