Final answer:
When 0.25 L of a 6.0 M HNO₃ solution is diluted to 2.0 L, the new solution has a molarity of 1.5 M.
Step-by-step explanation:
The question asks to find the molarity of a diluted solution of HNO₃. The initial volume of the 6.0 M HNO₃ solution is 0.25 L and it is diluted to a final volume of 2.0 L. To find the molarity of the new solution, we can use the dilution equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, respectively, and M2 is molarity and V2 is volume of the diluted solution.
By substituting the known values M1 = 6.0 M and V1 = 0.25 L, and V2 = 2.0 L into the equation and solving for M2, we can find the molarity of the diluted solution.
(6.0 M)(0.25 L) = M2(2.0 L)
Solving for M2 gives:
M2 = (6.0 M)(0.25 L) / 2.0 L
M2 = 1.5 M
Therefore, the molarity of the new solution is 1.5 M.