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A resistor is rated at 3,200Ω with a tolerance of +4%. The actual resistance is 3,020Ω. By what percent is the actual resistance below the low tolerance limit (Round to the nearest whole percent)?

a) 5%
b) 10%
c) 15%
d) 20%

User Xiaokaoy
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1 Answer

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Final answer:

The actual resistance is below the low tolerance limit by approximately 5% (rounded to the nearest whole percent).

Step-by-step explanation:

To find the percent by which the actual resistance is below the low tolerance limit, we need to calculate the difference between the actual resistance and the low tolerance limit, and then express it as a percentage of the low tolerance limit.

Given:

  • Resistance rating: 3,200Ω
  • Tolerance: +4%
  • Actual resistance: 3,020Ω

First, we need to find the low tolerance limit by adding the tolerance value to the resistance rating: 3,200Ω + (4% of 3,200Ω).

Next, we calculate the difference between the actual resistance and the low tolerance limit: Low Tolerance Limit - Actual Resistance.

Finally, we express this difference as a percentage of the low tolerance limit by dividing the difference by the low tolerance limit and multiplying by 100.

By following these steps, we can find the percent by which the actual resistance is below the low tolerance limit.

Answer: The actual resistance is below the low tolerance limit by approximately 5% (rounded to the nearest whole percent).

User Panktijk
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