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An object is kept at a distance of 5 cm in front of the convex mirror of focal length 10 cm. Calculate the position and magnification of the image and state its nature.

User Aerendir
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Final answer:

The position of the image is 10/3 cm away from the convex mirror, on the same side as the object, and the magnification is 2/3. The image is upright and virtual.

Step-by-step explanation:

To solve this problem, we can use the mirror equation: 1/f = 1/do + 1/di, where f represents the focal length, do represents the object distance, and di represents the image distance. Since the object is placed 5 cm in front of the convex mirror of focal length 10 cm, we have do = -5 cm and f = 10 cm.

Substituting these values into the mirror equation, we can solve for di:

1/10 = 1/-5 + 1/di

Simplifying this equation, we get:

1/di = 1/10 + 1/5

1/di = 3/10

di = 10/3 cm

The position of the image is 10/3 cm away from the convex mirror, on the same side as the object. To find the magnification, we can use the formula:

magnification (m) = -di/do

Substituting the values, we get:

m = - (10/3) / (-5) = 2/3

The magnification is 2/3. Since the magnification is positive, the image is upright, and since the object is closer to the mirror than the focal point, the image is virtual.

User Agathe
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