Final answer:
The mass of oxygen obtained from heating 439.09 g of potassium chlorate is approximately c. 384.64 g.
Step-by-step explanation:
To calculate the mass of oxygen obtained from heating 439.09 g of potassium chlorate (KClO3), we need to consider the molar ratios in the balanced chemical equation. The equation tells us that 2 mol of KClO3 produce 3 mol of O2. Additionally, we know that the molar mass of KClO3 is 122.55 g/mol and the molar mass of O2 is 32.00 g/mol.
By using these values and performing the appropriate calculations:
(439.09 g KClO3) x (3 mol O2 / 2 mol KClO3) x (32.00 g/mol O2) = 384.64 g O2
Therefore, the mass of oxygen obtained from heating 439.09 g of potassium chlorate is approximately 384.64 g (option c).