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Triangle ABC has vertices located at A(0, 2), B (2,5), and C (-1, 7).

Find the length of each side of the triangle. Show your work.

a. AB
b. BC
c. AC
d. Not enough information

User Entela
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1 Answer

4 votes

Final answer:

The lengths of the sides of triangle ABC are AB = √13, BC = √13, and AC = √26. We found these lengths using the distance formula, which is derived from the Pythagorean theorem.

Step-by-step explanation:

To find the length of each side of triangle ABC, we will use the distance formula which is derived from the Pythagorean theorem.

Length of AB

The length of side AB can be found using the coordinates of points A(0, 2) and B(2, 5). Applying the distance formula:

AB = √((x2 - x1)² + (y2 - y1)²)

AB = √((2 - 0)² + (5 - 2)²)
AB = √(4 + 9)
AB = √13

Length of BC

The length of side BC is found using the coordinates of points B(2, 5) and C(-1, 7):

BC = √((-1 - 2)² + (7 - 5)²)
BC = √(9 + 4)
BC = √13

Length of AC

For side AC using the coordinates of points A(0, 2) and C(-1, 7):

AC = √((-1 - 0)² + (7 - 2)²)
AC = √(1 + 25)
AC = √26

Therefore, the lengths of the sides of triangle ABC are as follows: AB = √13, BC = √13, AC = √26.

User Juanjo Berenguer
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