Final answer:
The probability that only one student passes math out of three random students is 0.384
Step-by-step explanation:
To find the probability that only one student passes math out of three random students, we need to use the binomial probability formula. The formula is:
P(X=k) = C(n,k) * p^k * (1-p)^(n-k)
Where X is the number of successes, n is the number of trials, p is the probability of success, and k is the specific number of successes we want to calculate the probability for.
In this case, X=1, n=3, and p=0.2. Plugging these values into the formula gives:
P(X=1) = C(3,1) * 0.2^1 * (1-0.2)^(3-1) = 3 * 0.2 * 0.8^2 = 0.384
Therefore, the probability that only one student passes math is 0.384. The correct answer choice is (B) 0.384.