Final answer:
The reaction of acetylene with d) Cl₂, then HBr, would give CH₂Br-CHBrCl as the product. This involves an initial addition of Cl2₂ across the acetylene triple bond, followed by an anti addition of HBr.
Step-by-step explanation:
The reaction of acetylene with which of the following gives CH₂Br-CHBrCl?
Acetylene (C₂H₂) is a colorless hydrocarbon known for its high reactivity due to the triple bonds between carbon atoms. The molecule can undergo addition reactions where the pi-bonds are broken, and new atoms are added to the carbon atoms.
The correct answer for producing CH₂Br-CHBrCl is d Cl₂, then HBr. This sequence of reactions involves an initial addition of chlorine (Cl₂) across the triple bond of acetylene, followed by the addition of hydrogen bromide (HBr) to the resulting product.
The Cl₂ would add to C₂H₂ to form CHCl=CHCl, which would then react with HBr to give CH₂Br-CHBrCl through an anti addition mechanism, ensuring the two halogens end up on opposite sides of the double bond.