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A gas cylinder containing 13 kg of butane gas has a capacity of 200 dm³ at 26 degrees Celsius and 200 atmospheres pressure. What volume will the gas occupy at STP (Standard Temperature and Pressure)?

a) 163.8 dm³
b) 200 dm³
c) 224 dm³
d) 273.15 dm³

1 Answer

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Final answer:

The volume of the gas at STP can be calculated using the combined gas law formula. Substituting the given values, we find that the gas will occupy a volume of 163.8 dm³ at STP.

Step-by-step explanation:

To calculate the volume of the gas at STP, we can use the combined gas law formula PV/T = PV/T. We can rearrange this equation to solve for V2, the final volume of the gas at STP:

V2 = (P1 * V1 * T2) / (P2 * T1)

Substituting the values given in the problem, we have:
V2 = (200 atm * 200 dm³ * 273.15 K) / (1 atm * 26 °C + 273.15 K)

V2 = 163.8 dm³

Therefore, the volume that the gas will occupy at STP is 163.8 dm³.

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