Question

Y= x+2/ln(4x^2−1)

​Find the values of x for which y is not defined.

a) x=−2, 2/1
​b) x=−1,2
c) x=−1,−2
d) x=0, 2/1

Answer 1

The values of x for which y is not defined in the equation y = x + 2/ln(4x^2-1) are x > 1/2 and x < -1/2.

Step-by-step explanation:

To find the values of x for which y is not defined in the equation y = x + 2/ln(4x^2−1), we need to determine the values of x that make the denominator 0.

The natural logarithm function, ln(), is undefined for negative values and 0. Therefore, the denominator 4x^2−1 must not be negative or equal to 0. Solving this inequality, we get:

4x^2−1 > 0

4x^2 > 1

x^2 > 1/4

x > 1/2 or x < -1/2

Therefore, the values of x for which y is not defined are x > 1/2 and x < -1/2.