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Use the following equation to help you answer the question. The peak intensity of radiation from a star named Omega is 4×10^5nm. What is the average surface temperature of Omega rounded to the nearest whole number?

1.0.137K
2.7.25K
3.11.6K
4. 1.16×10^11K

User BTagTiger
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1 Answer

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Final answer:

The average surface temperature of Omega, with peak radiation intensity at 4×105nm, is approximately 7.25K, determined by applying Wien's displacement law.

Step-by-step explanation:

To find the average surface temperature of a star named Omega with a peak intensity of radiation at 4×105nm, we can use Wien's displacement law, which states that the wavelength of the peak emission from a black body (λmax) is inversely proportional to the temperature (T). The law can be mathematically expressed as λmax T = b, where b is Wien's constant, approximately equal to 2.897×103nm·K. We can solve for T by dividing Wien's constant by the peak wavelength. By plugging in our known values, we get T = b / λmax = (2.897×103nm·K) / (4×105nm) ≈ 7.25K, after rounding to the nearest whole number.

So, the average surface temperature of the star Omega is approximately 7.25K, which is considerably lower than the surface temperature of the Sun.

User Hossein Heydari
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