Final answer:
To select a committee of 5 people from 10, with Jones already on it, calculate the combinations of choosing the remaining 4 members from 9, which is C(9, 4). The calculation yields 126 ways, but this is not one of the provided options.
Step-by-step explanation:
The subject of this question is Mathematics, specifically combinatorics, which deals with counting combinations and arrangements of items. Given that Jones must be on the committee and there are 10 people to choose from, Jones takes one spot on the committee, leaving 4 spots to be filled from the remaining 9 people.
To find the number of ways to choose a committee of 5 people with Jones already on it, we use the combination formula which is C(n, k) = n! / (k!(n-k)!) where n is the total number of items to choose from, k is the number of items to be chosen, and '!' represents factorial. Since we are choosing 4 more members from 9 (because Jones is already chosen), our equation becomes C(9, 4) = 9! / (4!(9-4)!).
Calculating this, we get 9! / (4! * 5!) = (9*8*7*6) / (4*3*2*1) = 126 different ways. However, since 126 is not one of the options provided, and the next closest answer is 252.