Final answer:
Two positive point charges, 0.1mm apart, repel each other with a force of 18 Newtons. Their separate values are q1 = 6 Coulombs and q2 = 3 Coulombs.
Step-by-step explanation:
Given that two positive point charges are 0.1mm apart and repel each other with a force of 18 Newtons, we can calculate their separate values.
Let's assume that the charges are denoted as q1 and q2. The sum of the charges is given as 9 Coulombs, so we have q1 + q2 = 9.
According to Coulomb's Law, the force of repulsion between the charges can be calculated as F = k * ((q1 * q2) / r^2), where k is the electrostatic constant and r is the distance between the charges. Rearranging the equation, we get q1 * q2 = (F * r^2) / k.
Substituting the given values, we have q1 * q2 = (18 * (0.1 * 10^-3)^2) / (9 * 10^9).
To find the values of q1 and q2, we can solve the quadratic equation q1^2 - 9q1 + 36 = 0. Solving this equation, we get q1 = 6 and q2 = 3.