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Nwosu borrows 7000 at the rate of 6% p.a compound interest. If he pays 1300 at the end of each year, how much is he owing at the end of the third year?

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Final answer:

Nwosu owes approximately $8346.11 at the end of the third year.

Step-by-step explanation:

To calculate the amount owed at the end of the third year, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where A is the final amount, P is the principal (initial amount borrowed), r is the annual interest rate (in decimal form), n is the number of times interest is compounded per year, and t is the number of years.

In this case, Nwosu borrows $7000 at an interest rate of 6% per year, compounded annually. The principal is $7000, the interest rate is 6% or 0.06, there is one compounding per year (n=1), and we are interested in the amount owed after 3 years (t=3).

Using the formula, we can calculate the final amount owed:

A = 7000(1 + 0.06/1)^(1*3) = 7000(1 + 0.06)^3 = 7000(1.06)^3 = 7000(1.191016) ≈ $8346.11

Therefore, at the end of the third year, Nwosu owes approximately $8346.11.

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