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Determine the possible blood types of the children resulting from the crossing of parents with the following genotype and include a Punnett Square:

A) All children will have blood type AB.
B) Children can have blood types A or B.
C) The blood types of the children cannot be determined.
D) Children will have blood type O.

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Final answer:

Children from AB blood type parents can have blood types A, B, or AB, following a phenotype ratio of 1A:2AB:1B. The correct answer is B) Children can have blood types A or B.

Step-by-step explanation:

When determining the possible blood types of children from parents with AB blood type (genotype IAIB), we need to consider the inheritance patterns of the ABO blood group system. The alleles IA and IB are codominant, and both express their traits fully when paired together. Hence, if both parents are of genotype IAIB, their children can have any of the following genotypes and corresponding blood types:

  • IAIA or IAi - Blood type A
  • IBIB or IBi - Blood type B
  • IAIB - Blood type AB

To create a Punnett Square to show these possible outcomes, each parent contributes one of two alleles, IA or IB, and the resulting combinations determine the child's genotype. This results in a phenotype ratio of 1A:2AB:1B (not considering the genotype) for possible blood types. Therefore, the correct answer to the question is B) Children can have blood types A or B.

When two individuals with AB blood type have children, the children can have blood types A, B, or AB. The genotype of the parents determines the possible blood types of the children. If both parents have genotype AB (homozygous), all the children will have blood type AB. If one parent has genotype A and the other has genotype B, the children can have blood types A or B. If one parent has genotypes A or B and the other parent has genotype O (ii), the children will have blood type O. The Punnett Square can be used to visualize the possible combinations of alleles and their resulting blood types.