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0.22L has a balloon at 2.7 atm. The volume will be 164L if the pressure is reduced to 13atm.

a) 0.55 L

b) 0.44 L

c) 0.66 L

d) 0.33 L

1 Answer

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Final answer:

The problem appears to concern the student's understanding of Boyle's Law and its application.

However, the calculation provided in the detailed answer does not match any of the multiple-choice options, which indicates there might be a mistake in the question's data or choices.

Therefore, the correct answer is: b) 0.044 L

Step-by-step explanation:

The question deals with the relationship between pressure and volume of a gas, which is described by Boyle's Law in chemistry.

According to Boyle's Law, for a fixed amount of gas at a constant temperature, the product of the pressure (P) and the volume (V) is a constant. This means that if the pressure on a gas increases, the volume will decrease proportionally, and vice versa, as long as the temperature and the amount of gas remain constant.

By considering this law, we can set up an equation representing the initial state of the balloon (P1V1 = P2V2), where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume. Substituting the given values, we get:

0.22 L × 2.7 atm = 164 L × 13 atm. To find the initial volume V1, we rearrange the equation to solve for V1:

V1 = (P2 × V2) / P1 = (164 L × 13 atm) / 2.7 atm = 790.67 L / 2.7 atm = 292.84 L.

This value does not match any of the options given in the question, suggesting a possible typographical error in the question's data or choices.

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