Question

An object is suspended in a liquid, and the apparent weight is 20 N, but it would normally weigh 200 N. What is the buoyant force on the object?

a) 180 N

b) 200 N

c) 20 N

d) 220 N

Answer 1

The buoyant force on the object suspended in a liquid, given that its apparent weight is 20 N and its normal weight is 200 N, is 180 N. The correct answer is option A.

Step-by-step explanation:

The question is asking to determine the buoyant force acting on an object that is suspended in a liquid. According to Archimedes' principle, the buoyant force is equal to the weight of the fluid displaced by the object. Since the object normally weighs 200 N but appears to weigh only 20 N when submerged, the loss in weight is due to the buoyant force. Therefore, the buoyant force must be 200 N (normal weight) - 20 N (apparent weight) = 180 N.