Question

A stone is projected vertically upwards with a speed of 5 m/s from the top of a tower of height 50 m. Neglecting air resistance, determine the maximum height it reached from the ground. (g=10 m/s²)

a) 25 m
b) 30 m
c) 40 m
d) 50 m

Answer 1

The stone reaches a maximum height of 25 m from the ground.

Step-by-step explanation:

To determine the maximum height reached by the stone, we can use the equation for vertical displacement:

Δy = vi2 / (2g)

Where Δy is the vertical displacement, vi is the initial velocity, and g is the acceleration due to gravity.

Given that the stone is projected vertically upwards with a speed of 5 m/s and the tower height is 50 m, we can plug in these values:

Δy = (5 2) / (2 * 10) = 25 m

Therefore, the stone reaches a maximum height of 25 m from the ground.