Question

A long straight conductor X carrying a current of 2A is placed parallel to a short conductor Y of length 0.05m carrying a current of 3A. Calculate the flux density if the conductors are separated by 0.10m.

a) 1.2 × 10^-4 T

b) 2.4 × 10^-4 T

c) 3.6 × 10^-4 T

d) 4.8 × 10^-4 T

Answer 1

The magnetic flux density between the two parallel conductors can be calculated using the formula B = (μ₀ × I₁ × I₂)/(2π × d), where μ₀ is the permeability of free space, I₁ and I₂ are the currents, and d is the separation between the conductors. Plugging in the values, we find that the flux density is 1.2 × 10^-4 T.

Step-by-step explanation:

To calculate the flux density between two parallel conductors carrying currents, you can use the formula:

B = (μ₀ × I₁ × I₂)/(2π × d)

• Where B is the magnetic flux density
• μ₀ is the permeability of free space (4π × 10^-7 T·m/A)
• I₁ and I₂ are the currents in the conductors (2A and 3A in this case)
• d is the separation between the conductors (0.10m in this case)

Plugging in the values, we get:

B = (4π × 10^-7 T·m/A × 2A × 3A)/(2π × 0.10m) = 1.2 × 10^-4 T

Therefore, the correct answer is 1.2 × 10^-4 T.