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Determine the total shrink (TS) of an offset with a bend angle of 22.5° and a rise (R) of 5.5 inches. (Round your FINAL answer to two decimal places.)

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The total shrink (TS) for an offset with a bend angle of 22.5° and a rise of 5.5 inches is approximately 0.42 inches when rounded to two decimal places.

To determine the total shrink (TS) of an offset with a bend angle of 22.5° and a rise (R) of 5.5 inches, we typically use the formula:

TS = R ( 1 - cos( θ))

Where R is the rise and θ is the bend angle in radians. First, we need to convert the bend angle from degrees to radians by multiplying by (π/180).

22.5° × (π / 180) = 22.5 x 0.01745 = 0.3927 radians.

Now, we calculate the cosine of 0.3927 radians and then find the total shrinkage.

cos(0.3927) ≈ 0.9239

TS = 5.5 inches ( 1 - 0.9239 ) ≈ 5.5 inches × 0.0761 ≈ 0.41855 inches.

Round the resultant TS to two decimal places, we get:

TS ≈ 0.42 inches.

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