153k views
0 votes
Equal pressure in a hydraulic system enters two cylinders. The piston in cylinder number 1 is 2 inches in diameter, and the piston in cylinder 2 has a 2 inch radius. Which piston can move a heavier load?

User Rspencer
by
7.3k points

1 Answer

4 votes

Final answer:

The piston with the larger area can move a heavier load in a hydraulic system.

Step-by-step explanation:

In a hydraulic system, the force applied is determined by the pressure and the area on which the pressure is applied.

The equation that relates the force, pressure, and area is: force = pressure * area.

Since the pressure is the same in both cylinders, the piston with the larger area will be able to move a heavier load.

In this case, cylinder number 2 has a radius of 2 inches, which means its diameter is 4 inches.

The formula for calculating the area of a circle is: area = π * radius^2.

Therefore, the area of cylinder number 2 is: area = π * (2^2).

Cylinder number 1 has a diameter of 2 inches, so its radius is 1 inch, and the area of cylinder number 1 is: area = π * (1^2).

Since the area of cylinder number 2 is larger than the area of cylinder number 1, the piston in cylinder number 2 can move a heavier load.

User Niels Keurentjes
by
8.5k points