Question

A container with a volume of 3 liters contains a gas at 27°C and 2 atmospheric pressure. Find the work that the gas does during the following operations: a) Its temperature is increased 5 times in constant volume b) From its initial state, its volume is increased to 4 times at constant pressure. c) Volume is doubled from the beginning.

Answer 1

The question pertains to calculating the work done by a gas during various thermodynamic processes, including constant volume and constant pressure scenarios, using the applicable physics equations.

Step-by-step explanation:

The question relates to the thermodynamics of gases and involves calculating the work done by a gas during various processes. Given scenarios include changes in temperature at constant volume, expansion at constant pressure, and a general expansion that doubles the volume. Using the principles of thermodynamics:

• (a) At constant volume, no work is done when the temperature increases, as work (W) is given by W = PΔV, and ΔV is zero.
• (b) For expansion at constant pressure, the work done by the gas can be found by W = PΔV with the values of P and ΔV known or calculable from ideal gas law.
• (c) For a general volume expansion, the work done would also depend on the specifics of the process, such as whether it is isothermal, adiabatic, etc. If it's an isothermal expansion, the work can be calculated using W = nRT ln(V2/V1).