Final answer:
In the reduction half-reaction O2 + electrons → 2O2-, four electrons are gained by the oxygen molecule to form two oxide ions.
Step-by-step explanation:
The half-reaction for the reduction of oxygen to oxide ions is:
O2 + 4e- → 2O2-
In this half-reaction, each oxygen molecule (O2) gains four electrons (4e-) to form two oxide ions (2O2-). The electrons gained in the reduction half-reaction must equal the number of electrons lost in the accompanying oxidation half-reaction in order for the reaction to be balanced. This process ensures that the overall charge is conserved, as well as the balance in terms of the atoms involved.