Question

What is the solution set to the following equation?

x^4+2x−48=0

a. +2i√2, +√6
b. two, +12)
c. +2i√2, +3)
d. i√3, +2√2

Answer 1

The solution set to the equation x^4+2x-48=0 is x = 3, x = -4, +2i√2, +3.

Step-by-step explanation:

The equation x4 + 2x - 48 = 0 is a quartic equation. To solve it, we need to factor it or use the rational root theorem. In this case, we can factor the equation as (x - 3)(x + 4)(x2 + 3x + 4) = 0. So the solution set is x = 3, x = -4, and the quadratic equation has no real solutions, only complex solutions.

Therefore, the correct option is c. +2i√2, +3.