Question

Factorize the following expressions by grouping them in pairs 15ab-10b-12a-8

A. (5a−4)(3b−2)(5a−4)(3b−2)
B. (3a−2)(5b−4)(3a−2)(5b−4)
C. (15a−12)(b−8)(15a−12)(b−8)
D. (15a−10)(b−8)(15a−10)(b−8)

Answer 1

To factorize 15ab-10b-12a+8 by grouping, we find common factors in pairs, leading to the factored form (3a-2)(5b-4), which corresponds to option B.

Step-by-step explanation:

The expression that needs to be factorized by grouping in pairs is 15ab-10b-12a+8. To do this, we will look for common factors in pairs of terms. First, we group the terms 15ab and -10b together, and then we group -12a and 8 together. Factorizing the first pair by taking 5b common, we get 5b(3a-2). Likewise, factorizing the second pair by taking -4 common, we get -4(3a-2). Notice that both groups now contain the term (3a-2). The expression can be factorized as (3a-2)(5b-4), which gives us option B.