Question

How can the number of loops be reduced, possibly into one loop, in the given solution for calculating the maximum sum of hourglasses in a 2D array?

A) Utilize a nested for loop instead of a do-while loop
B) Use Array.map() to iterate over the rows of the 2D array
C) Implement a recursive function to handle the iteration
D) Use a single loop with appropriate index calculations for the hourglass pattern

Answer 1

To reduce the number of loops and combine them into one for calculating the maximum sum of hourglasses in a 2D array, use a single loop with appropriate index calculations for the hourglass pattern.

Step-by-step explanation:

In order to reduce the number of loops and possibly combine them into one loop for calculating the maximum sum of hourglasses in a 2D array, option D) should be implemented. This option suggests using a single loop with appropriate index calculations for the hourglass pattern. By iterating through the 2D array and calculating the sum of each hourglass using a single loop, the efficiency of the solution can be improved.